A sample of NO2 in a 1550 mL metal cylinder at 70.26 kPa has its temperature changed from 480oC to -237oC while its volume is simultaneously changed by a piston to 5114 mL. What is the final pressure in kPa?

The final pressure is 1.01325 kPa

Explanation:

Step 1: Data given

Volume of the metal cylinder = 1550 mL = 1.550 L

Initial Pressure = 70.26 kPa = 0.69341229 atm

Initial temperature = 480 °C = 753 K

The temperature lowers to -237 °C = 36 K

The volume increases to 5114 mL = 5.114L

Step 2: Calculate the final pressure

P1*V1 / T1 = P2*V2/T2

⇒with P1 = the initial pressure = 0.69341229 atm

⇒with V1 = the initial volume = 1.550 L

⇒with T1 = the initial temperature = 753 K

⇒with P2 = the final pressure = TO BE DETERMINED

⇒with V2 = the final volume = 5.114 L

⇒with T2 = the final temperature = 36 K

P2 = 0.0100 atm = 1.01325 Kpa

The final pressure is 1.01325 kPa

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

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