For the reaction POCl3(g) ⇀↽ POCl(g) + Cl2(g) Kc = 0.30. An initial 0.3 moles of POCl3 are placed in a 3.1 L container with initial concentrations of POCl and Cl2 equal to zero. What is the final concentration of POCl3? 1. final concentration = 0.281774 M 2. final concentration = 0.077 M 3. final concentration = 0.185 M 4. final concentration = 0.039534 M 5. final concentration = 0.019767 M

The final concentration of is 0.019767 M

Explanation:

Molarity is calculated by using the equation:

Initial moles of = 0.3 moles

Volume of solution = 3.1 L

For the given chemical equation:

Initial:                0.097

At eqllm:         0.097-x             x              x

The expression of for above equation follows:

We are given:

Putting values in above expression, we get:

Neglecting the negative value of 'x' because concentration cannot be negative.

So, final concentration of = (0.097 - x) = (0.097 - 0.077233) = 0.019767 M

Hence, the final concentration of is 0.019767 M

first one is the correct answer