Suppose a current of 250.mA is passed through an electroplating cell with an aqueous solution of Ag2SO4 in the cathode compartment for 52.0 seconds. Calculate the mass of pure silver deposited on a metal object made into the cathode of the cell.

Explanation:

The first step is to know what is the half-reaction of silver, so:

Therefore, the half-reaction is:

The next step is the calculation of the amount of charge, so:

Now, we can calculate the mass, we have to keep in mind that we have 1 mol of electrons for each mol of

b. acid is the correct answer @jayxboof all social media

acid : acids are those which accepts an electron-pairs.

base : bases are those which donates ab electron-pairs.

alkali : it is a base that dissolves in water. it is basically a base and the ph greater than 7.

hydroxide ion : it is a poly-atomic ion which is negatively charged.

law of conservation of matter