Write the net ionic equation for this precipitation reaction. Include physical states. 2 LiCl ( aq ) + Pb ( CH 3 COO ) 2 ( aq ) ⟶ PbCl 2 ( s ) + 2 LiCH 3 COO ( aq )

2Cl⁻(aq) + Pb²⁺(aq) → PbCl₂ (s)

Explanation:

The molecular equation is:

2 LiCl (aq) + Pb(CH₃COO)₂ (aq)  →  PbCl₂ (s) ↓ + 2LiCH₃COO (aq)

We identify that a compound that is formed has a different state from the others, so a state change has been produced.

We dissociate all the reactants and the products except for that solid compound

2LiCl(aq) → 2Li⁺(aq) + 2Cl⁻(aq)

Pb(CH₃COO)₂ (aq)  →  Pb²⁺(aq)  +  2CH₃COO⁻(aq)

2LiCH₃COO (aq)  → 2Li⁺(aq)  +  2CH₃COO⁻(aq)

We write the complete ionic equation:

2Li⁺(aq) + 2Cl⁻(aq) + Pb²⁺(aq)  +  2CH₃COO⁻(aq) → PbCl₂ (s) + 2Li⁺(aq)  +  2CH₃COO⁻(aq)

We eliminate the spectators ions, so the net ionic equation is:

2Cl⁻(aq) + Pb²⁺(aq) → PbCl₂ (s)

answer: h+ its less than oh

explanation: