A sample of air occupies 3.8 L when the pressure is 1.2 atm and temperature at 25 Celsius. What pressure( in atm) will the gas have at 100 Celsius when the volum is held constant?

Answer : The final pressure of the gas will be, 1.5 atm

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

or,

where,

= initial pressure of gas = 1.2 atm

= final pressure of gas = ?

= initial temperature of gas =

= final temperature of gas =

Now put all the given values in the above equation, we get:

Thus, the final pressure of the gas will be, 1.5 atm

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.