Wet steam at 1100 kPa expands at constant enthalpy (as in a throttling process) to 101.33 kPa, where its temperature is 105°C. What is the fraction of the steam in its initial state?

93%

Explanation:

Hello,

In this case, based on the second state, at 101.33 kPa and 105 °C a saturated vapor is formed, which has an enthalpy of:

Now, since such condition was attained at constant enthalpy, the previous enthalpy equals the mixture's enthalpy at 1100 kPa, thus, for such condition:

In such a way, the quality , or fraction of the steam at the initial condition turns out:

Best regards.

specific gravity is the density of a substance divided by the density of water. since (at standard temperature and pressure) water has a density of 1 gram/cm3, and since all of the units cancel, specific gravity is usually very close to the same value as density

so "c" is the answer

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it means there are 3 atoms of oxygen