Determine the point groups for a. Ethane (staggered conformation) b. Ethane (eclipsed conformation) c. Chloroethane (staggered conformation) d. 1,2-Dichloroethane (staggered anti conformation)

Answer and Explanation:

Every molecule has a set of symmetry operations that helps in determining its overall symmetry. This set of operations determines the point group of a molecule.

(a) Ethane (staggered conformation)

Ethane in the staggered conformation has:

hence the point group of ethane in staggered conformation is  

(b) Ethane (eclipsed conformation)

Ethane in the eclipsed conformation has:

Hence the point group of ethane in eclipsed conformation is

(c) chloroethane (staggered conformation)

Chloroethane in the staggered conformation has:

Hence the point group of staggered conformation in chloroethane is

(c) 1,2-Dichloroethane (staggered anti conformation)

1,2-Dichloroethane in the staggered anti conformation has:

Hence the point group in the staggered anti conformation of 1,2-Dichloroethane is

e

explanation:

answer is: empirical formula is tl₂o. if we use 100 grams of compound, tha:

m(tl) = 96.2%  · 100 g ÷ 100%.

m(tl) = 96.2 g.

n(tl) = m(tl)  ÷ m(tl). n(tl) = 96.2 g  ÷ 204.4 g/mol.

n(tl) = 0.47 mol. m(o) = 3.77 g. n(o) = m(o)  ÷ m(o). n(o) = 3.77 g  ÷ 16 g/mol. n(ag) = 0.235 mol. n(tl) . n(o) = 0.47 mol : 0.235 mol /0.235. n(tl) . n(o) = 2 : 1.

m(tl₂o) = 204.4 g/mol  · 2 + 16 g/mol = 424.8 g/mol.

m(compound) = 456. 8 g/mol - 424.8 g/mol = 32 g/mol ( 2 oxygens); tl₂o₃.