Determine the amount of energy (heat) in joules required to raise the temperature of 5 kg of iron from 50°C to 200°C.

333,000 Joules is the amount of energy (heat) in joules required to raise the temperature of 5 kg of iron from 50°C to 200°C.

Explanation:

Data given:

mass of iron 5 Kg or 5000

initial temperature = 50 degree centigrade

final temperature = 200 degrees centigrade

change in temperature (Δ T= 200 -50 degrees centigrade)

                                         = 150 °C

cp  (specific heat capacity of iron) = 0.444j/gram C

q (heat supplied) = ?

applying the formula,

q=mcΔT

putting the values in the equation:

q = 5000 X 0.444 X150

 q  = 333,000 Joules of energy.

The heat required 333,000 Joules of energy is required.

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