G During a coarse titration, you placed 60 mg of unknown acid in 120 mL water, and dispensed 20 mL of NaOH to this acid solution (analyte) to reach the endpoint. What should be the mass and volume of the analyte so it takes 10 mL of NaOH to reach the endpoint

Volume of an analyte solution is 60 mL.

30 mg is the mass of unknown acid was present in an analyte.

Explanation:

According to question , 120 mL of unknown acid solution was mixed with 20 NaOH solution to reach its endpoint.

Then 10 mL of NaOH will bring the end point of :

unknown acid solution.

Volume of an analyte solution is 60 mL.

Mass of unknown acid = 60 mg

Volume of the solution of unknown acid = 120 mL

 Concentration of unknown acid acid solution:

=

Then 60 mL of unknown acid solution will have:

30 mg is the mass of unknown acid was present in an analyte.

the product of the pressure and volume is also constant

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