How many milliliters of a 2.00 M KBr are needed to prepare 250.0 mL of 0.60 M KBr?

75mL

Explanation:

Data obtained from the question include:

C1 = 2M

V1 =?

C2 = 0.60M

V2 = 250mL

The original volume of solution can be obtained as follows:

C1V1 = C2V2

2 x V1 = 0.6 x 250

Divide both side by 2

V1 = (0.6 x 250) / 2

V1 = 75mL

The volume needed is 75mL

distance, luminosity, brightness, radius, chemical composition, and temperature

answer; the numbers of valence electrons in the acetic acid molecule (ch3co2h) is 24;