Classify each of the following as a combination, decomposition, single replacement, double replacement, or combustion reaction:

Sort these reactions into the proper categories.

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Fe2O3(s)+3C(s)⟶2Fe(s)+3CO(g)Fe2O3 (s)+3C(s)⟶2Fe(s)+3CO(g)

C2H4(g)+3O2(g)⟶Δ2CO2(g)+2H2O(g)C2 H4(g)+3O2(g)⟶Δ2CO2(g)+2H2O(g)

Fe2O3(s)+6HCl(aq)⟶2FeCl3(aq)+3H2O (l)Fe2O3(s)+6HCl(aq)⟶2FeCl3(aq)+3H2 O(l)

2Al(s)+3Br2(l)⟶2AlBr3(s)2Al(s)+3B r2(l)⟶2AlBr3(s)

C6H12O6(s)⟶6C(s)+6H2O(g)C6H12O6(s )⟶6C(s)+6H2O(g)

1) single replacement

2) combustion reaction.

3) double replacement reaction

4) combination reaction

5) decomposition reaction

Explanation:

Chemical equation:

Fe₂CO₃ + 3C  →   2Fe + 3CO

The given reaction is single replacement reaction. In this reaction carbon react with Fe₂CO₃ and replace the iron from CO₃²⁻ and form free iron and carbon monoxide.

Chemical equation:

C₂H₄ + 3O₂   →  2CO₂ + 2H₂O

The given reaction is combustion reaction. In which ethene burn in the presence of oxygen form carbon dioxide and water.

Chemical equation:

Fe₂O₃ + 6HCl   →  2FeCl₃ + 3H₂O

The given reaction is double replacement reaction. In which anion and cation of both reactants exchange with each others.

Chemical equation:

2Al + 2Br₂ →  2AlBr₃

The given reaction is combination reaction in which aluminium and bromine combine to form aluminium bromide.

Chemical equation:

C₆H₁₂O₆   →    6C + 6H₂O

The given reaction is decomposition reaction in which glucose molecule decompose to give water and carbon.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.

a physical change biology

explanation: