Calculate the mass of Cu deposited by the electrolysis of CuCl2 at 4A for 40 minutes.

3.16g

Explanation:

Data obtained from the question include:

I = 4A

t = 40mins = 40 x 60 = 2400secs

Q =?

Q = It

Q = 4 x 2400

Q = 9600C

Now let us generate a balanced half equation to determine the number faraday needed to deposit metallic Cu. This is illustrated:

Cu^2+ + 2e —> Cu

From the equation,

2 faraday is needed to deposit metallic cu

1 faraday = 96500C

Therefore 2 faraday = 2 x 96500 = 193000C

Molar Mass of Cu = 63.5g/mol

193000C deposited 63.5g of Cu

Therefore, 9600C will deposit = (9600 x 63.5)/193000 = 3.16g of Cu

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.

a is the correct answer