Find the pH of each mixture of acids. Acid Ionization Constants (Ka) for Some Monoprotic Weak Acids at 25 ∘C Acid Formula Ka Benzoic acid HC7H5O2 6.5×10−5 Hydrofluoric acid HF 6.8×10−4 Phenol HC6H5O 1.3×10−10 Formic acid HCHO2 1.8×10−4 Hypochlorous acid HClO 2.9×10−8

Find the pH of each mixture of acids. Acid Ionization Constants (Ka) for Some Monoprotic Weak Acids at 25 ∘C Acid Formula Ka Benzoic acid HC7H5O2 6.5×10−5 Hydrofluoric acid HF 6.8×10−4 Phenol HC6H5O 1.3×10−10 Formic acid HCHO2 1.8×10−4 Hypochlorous acid HClO 2.9×10−8

A.) 0.070 M in HNO3 and 0.185 M in HC7H5O2 Express your answer to two decimal places.

B.) 0.025 M in HBr and 0.020 M in HClO4 '

C.) 0.095 M in HF and 0.230 M in HC6H5O

a) the pH of the mixture = 1.13

b) the pH of this mixture  = 1.35

c) the pH of this mixture  = 2.09

Explanation:

The formula to determine the hydrogen ion concentration in benzoic acid is as follows:

HNO₃ is a strong acid whose dissociation is complete and thorough into its ions.

So, = 0.070 M

The total hydrogen concentration of the mixture will now be:

= (0.0035 + 0.070 )M

= 0.0735 M

Now the pH can be determined as:

pH = - log

pH = - log [0.0735]

pH = - (-1.13)

pH = 1.13

Hence, the pH of the mixture = 1.13

b) In HBr and HClO₄, these are both strong acids and as such, they undergo complete dissociation of their ions.

So,

So,

The total hydrogen ion concentration of the mixture =

Now; the pH will be

pH = - log

pH = - log [0.045]

pH = - (-1.35)

pH = 1.35

Thus, the pH of this mixture  = 1.35

c) For hydrofluoric acid and phenol (weak acids ), the following expression is used to calculate the hydrogen ion concentration

The pH can then be calculated as follows:

pH = - log

pH = - log  [0.008037]

pH = - (-2.09)

pH = 2.09

Thus, the pH of this mixture  = 2.09

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.