An isotope contains 26 protons , 24 electrons and 32 neutrons what is the identity of the isotope?

The isotope is identified as 58 Fe²⁺, where 58 is the mass number of the isotope.

Explanation:

In this problem, there is difference in the number of protons and electrons, but the electron number should not vary in a stable isotope. As isotopes are meant to have difference in number of neutrons leading to change in the mass number. So this means, in the present case the isotope is in oxidized state as the number of electrons is less than the number of protons. This indicates that the isotope is in +2 oxidation state, since the difference in the number of protons and electrons is 2.

Then as an isotope will be formed by varying in the number of neutrons for the elements in periodic table. So from the number of protons we can confirm the atomic number of the element. As the atomic number is given as number of protons in case of oxidized element, the atomic number of 26 in the present case will be related to Fe element in the periodic table.

Hence the isotope will be Fe in +2 oxidation state and having the atomic number as 26 and mass number as 26+32 = 58. So there is a change in the mass number of the isotope of Fe from 56 to 58.

Thus, the isotope is identified as 58 Fe²⁺, where 58 is the mass number of the isotope.

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3