Suppose you heat 100g of room temperature water in a small beaker and 1000g of room temperature water in a large beaker until the temperature of each is 60oC. A) Do the water molecules in the small beaker move as fast as those in the large beaker? B) Did both beakers of water gain the same amount of heat

Explanation:

Q = m × Cp × delta T

Where,

Q is the heat gained by water

m is the mass of water

Cp = specific heat capacity of water

= 4.18 kJ per kilogram per degree Celsius (J/kg°C).

This means that it takes 4,180 J to raise the temperature of 1 kg of water by 1°C

delta T is the difference in temperature

A.

The smaller beaker had a bigger temperature rise because the same energy has been given to a smaller number of water particles in the beaker than those particles in the large beaker so each particle is moving faster than those in the other beaker.

B.

Since both beakers were heated at the same time, they both gain the same amount of energy.

Qlarge = Qsmall

2b2t

explanation:

2b2t

the answer is 0.8m.

by: nicholas