The following unbalanced chemical equation is:

2 atoms of H + 2 atoms of I yields 1 atom of H and 1 atom of I

Write a balanced equation for this reaction using the smallest coefficients possible.

H2 + I2 —> 2HI

Explanation:

From the information provided, the equation can be written as:

H2 + I2 —> HI

Now, the equation can be balance as follows:

There are 2 atoms of H on the left side and 1atom on the right. It can be balance by putting 2 in front of HI as shown below:

H2 + I2 —> 2HI

Now the equation is balanced as there are equal numbers of atoms of the different elements present on both sides of the equation

Explanation:

Given the following reactants;

Two(2) atoms of Hydrogen, H

Two(2) atoms of Iodine, I

Now, we will balance the above equation with the smallest coefficients possible;

In the reaction above, Hydrogen and Iodine reacts to form a chemical compound called Hydrogen Iodide.

first dissociates into 2 iodine atoms, which each attach themselves to a side of an molecule and break the Hydrogen-Hydrogen bond.

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.

i think its 100.

hope this !