The rate law for the decomposition of ozone to molecular oxygen is rate = k[O3]2 [O2] The mechanism proposed for this process is O3 0001 O + O2 O + O3 2O2 What is the rate law in terms of k1, k2, and k−1? Be sure to simplify the rate law before inputting your answer.

The rate law is k =

Explanation:

From the mechanism is necessary to derive the rate law from the elementary steps and explain the effects of [O2] on the rate

The first step is a reversible reaction. Assuming dynamic equilibrium is achieved, the rate of the forward reaction is equal to the rate of the backward reaction

rate(forward) = rate(backward)

k1 [O3] = k-1 [O] [O2]

[O] is not part of the rate law, so we need to express [O] in terms of other species

[O] =

from the second step

rate = k2[O] [O3]

substituting [O] from the first step

rate =

k =

The final rate law is then

k =

So, as the concentration os O2 increase the rate decrease. Also from the first step of the mechanism we can se that O2 can react to O to form back the reactant O3 resulting in decreased reaction rate.

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