Suppose a current of 60. A flows through a copper wire for 22.0 minutes. Calculate how many moles of electrons travel through the wire. Be sure your answer has the correct unit symbol and the correct number of significant digits.

 0.821 moles

Explanation:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains number of particles.

We know that:

Charge on 1 electron =

Charge on 1 mole of electrons =

To calculate the charge passed, we use the equation:

where,

I = current passed = 60 A

q = total charge = ?

t = time required = 22.0 minutes =

Putting values in above equation, we get:

As 96500 C contains = 1 mole of electrons

79200 C contains = mole of electrons

Thus 0.821 moles of electrons travel through the wire.

here we have to get the change of moles on decrease the volume of the reaction in gas phase.

the   per the given options it will decrease by (d) 11-50%

we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:                   1 - α               α               α           = 1 + α

(concentration = moles/volume, as volume is 1 l)

(where α is the degree of dissociation)

now the dissociation constant in terms of concentration is :

=  

or,

or,   = (at v = 1l)

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:               (1 - α)/0.5           α/0.5         α/0.5       = (1 + α)/0.5

thus, the dissociation constant in terms of concentration is :

or,  

=  

so, the change of 1 : 1/0.5

or, 1: 2

thus it will decrease by 50%.

or, as per the given options it will decrease by 11-50%

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