In an experiment similar to the one described in this procedure, a saturated solution of Mg(OH)2 was titrated with 0.0500 M HCl solution. The equivalence point was reached when 0.330 mL of the acid had been added to 50.00 mL of the saturated Mg(OH)2.

The question is incomplete. The complete question is:

In an experiment similar to the one described in this procedure, a saturated solution of Mg(OH)2 was titrated with 0.0500 M HCI solution. The equivalence point was reached when 0.330 mL of the acid had been added to 50.00 mL of the saturated Mg(OH)2 1. How many moles of H+ were added? How many moles of OH were present in the initial solution of magnesium hydroxide? 2. What are the concentrations of OH and Mg2 in the original 50.00 mL solution? 3 Write the equation for dissolving Mg(OH)2 in water 4. Write the corresponding Ksp expression. 5. What is the value of Ksp found from the experimental data above?

Ksp=5.4×10-8

Explanation:

We must find find the concentration of base from the information provided. Then we can now find the concentration of hydrogen ions in the acid, concentration of magnesium ions and hydroxide ions in the base and finally the solubility product of the magnesium hydroxide solution as required. See image attached for more details of the solution to the problem.

answer : the correct answer is 2) hno₃ and naoh .

arrhenius concept of acid and base :

acid :

according to arrhenius acid are those which release h⁺ or hydronium ion (h₃o⁺) in aqueous solution .

example : hcl +h₂o ↔ h₃o⁺ + cl⁻

hcl is giving h₃o⁺ ion in water , hence it is an arrhenius acid .

base :

according to arrhenius , bases are those which releases oh⁻ ions in aqueous solution .

example : koh (aq) ↔ k⁺ + oh⁻

since koh is producing oh⁻ ions hence , it is an arrhenius base .

checking the options :

1) ch₃oh and naoh :

ch₃oh is known as methanol , an organic compound , which is neutral compound . the dissociation of ch₃oh is negligible . it is very very weak acid (ka = 3.2 * 10 ⁻¹² ) .

naoh being ionic gives na⁺ and oh⁻ ions in aqueous solution as :

naoh ↔ na⁺ + oh⁻ . hence it is an arrhenius base

it can be concluded that ch₃oh and naoh is not arrhenius acid and base.

2) hno₃ and naoh :

hno₃ is an ionic compound which gives ions h⁺ and no₃⁻ ion in aqueous solution as:

hno₃ + h₂o ↔ h₃o⁺ + no₃⁻

since it is giving h⁺ ion . hno₃ is arrhenius acid .

naoh being ionic gives na⁺ and oh⁻ ions in aqueous solution as :

naoh ↔ na⁺ + oh⁻

. hence it is an arrhenius base .

it can be said that hno₃ and naoh are arrhenius acid and base.

3) ch₃oh and hcl

as discussed ch₃oh is neutral compound .

while hcl in aqueous solution dissociates to give h⁺ and cl⁻ ions as :

hcl + h₂o→ h₃o⁺ + cl⁻ . so hcl is arrhenius acid .

hence , ch₃oh and hcl are not arrhenius acid and base.

4) hno₃ and hcl :

hno₃ as discussed gives h⁺ in aqueous solution , while hcl also gives h⁺ in aqueous solution .

hence both hno₃ and hcl are arrhenius acid they are not acid and base .

so the arrhenius acid and base are 2) hno₃ and naoh.