Write the dissolution reaction for manganese(II) chloride in water. Use the pull-down menus to specify the state of each reactant and product. + Is manganese(II) chloride considered soluble or not soluble ? ... ... A. Soluble ... B. Not soluble Based upon this, the equilibrium constant for this reaction will be: ... ... A. Greater than 1 ... B. Less than 1

See explanation for detailed answer.

Explanation:

MnCl2(s) + 6H2O <> [Mn(H2O)6]2+(aq) + 2Cl- (aq)

MnCl2 is soluble in water hence the equilibrium constant for the reaction will be greater than one.

It dissolves in water to form the complex stated above thereby tilting the pH of the solution towards the slightly acidic end.

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.

i believe the answer is 5,000