A 3.0-L gas mixture contains 30.% oxygen and 70.% nitrogen. Use the ideal gas law to determine the number of moles of oxygen at 2.0 atm and 400-K.

The number of moles of oxygen gas comes out to be 0.0548 mole

Explanation:

Given volume of gas = V = 3.0 L

The mixture contains 30 % oxygen gas by mole.

Pressure of mixture of gas =  P = 2.0 atm

Temperature = T = 400 K

Assuming n be the total number of moles of the mixture of gas.

The ideal gas equation is shown below

The mixture contains 30% oxygen gas by mole

Number of moles of oxygen gas is 0.0548 mole

explanation:

i think option no d is the correct answer