Suppose 650.mmol of electrons must be transported from one side of an electrochemical cell to another in 10.0 minutes. Calculate the size of electric current that must flow.

The size of electric current must 104.5 Ampere.

Explanation:

Moles of electrons = 650 mmol =

mmol = 0.001 mol

1 mol = atoms/ions

Number of electrons = N

N =

Charge on an electron =

Total charge on N electrons = Q

Duration of time = T = 10 min = 10 × 60 s

1 minute = 60 seconds

The size of electric current must 104.5 Ampere.

on passing the small ampere of electric current through the tube made of ar and hg of cfl generates uv rays which excites the fluorescent and thus emits the high radiation by consumption of just 5- 12 w in comparison to incandescent light which requires more power such as around 40 - 55 w to lighten.

moreover the life span of fluorescent or cfl is around 8000 h whereas the life span of incandescent is around 1200 h

hence, the building installed with incandescent lights bears more electricity bill.

alchemy hadn't scientific methods of study, appeal to mysticism and fantasy, the knowledge of chemistry and physics were modest at that time.

alchemy was - but as new rules were discovered it either changed into chemistry or it became "unscientific".