A 5.00g quantity of a diprotic acid was dissolved in water and made up exactly 250 mL. Calculate the molar mass if the acid is 25.0 mL of this solution required 11.1 mL of 1.00 KOH for neutralization. Assume both protons of the acid were titrated.

The molar mass of the diprotic acid is 90.10 g/mol.

Explanation:

The acid is 25.0 mL of this solution required 11.1 mL of 1.00 KOH for neutralization.

To calculate the concentration of acid, we use the equation given by neutralization reaction:

 ( neutralization )

where,

are the n-factor, molarity and volume of diprotic acid

are the n-factor, molarity and volume of base which is KOH.

We are given:

Putting values in above equation, we get:

Molarity of acid solution = 0.222 M =0.222 mol/L

Volume of original solution = 250 mL = 0.250 L ( 1 mL = 0.001 L)

Moles of diprotic acid in 0.250 L solution :

Mass of diprotic acid = m = 5.00 g

The molar mass of the diprotic acid is 90.10 g/mol.

може ли да зареждате повече информация, моля

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.