Provided that the molar mass of a compound is 543.52 g/mol, how many mg do you need to add to 17 mL of solvent to yield a solution molarity of 3 M?

N. B. M = (mol/L)
Select one:
a. 10.66
b. 27719520.00
c. 27.72
d. 27719.52
e. 3079946.67

27719.52 mg

Explanation:

From the question, we have;

Required to determine the mass of the compound needed to make the solution.

We know that;

Molarity = Moles ÷ Volume

Therefore;

Moles = Molarity × Volume

Hence;

Moles of the compound = 3 M × 0.017 L

                                         = 0.051 Moles

But;

Mass = Moles × Molar mass

        = 0.051 moles × 543.52 g/mol

        = 27.71952 g

But, 1 g = 1000 mg

Therefore;

Mass (in mg) = 27719.52 mg

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

geosphere and hydrosphere.

this is because the geosphere has to do with geological events, while the hydrosphere controls all water on earth.