A Assuming the reaction is first order in sucrose, determine the mass of sucrose that is hydrolyzed when 2.50 LL of a 0.180 MM sucrose solution is allowed to react for 200 minmin .

The question is incomplete, here is the complete question:

The hydrolysis of sucrose into glucose and fructose in acidic water has a rate constant of 1.8×10⁻⁴ s⁻¹ at 25°C. Assuming the reaction is first order in sucrose, determine the mass of sucrose that is hydrolyzed when 2.65 L of a 0.120 M sucrose solution is allowed to react for 200 min.

The mass of sucrose solution left is 12.56 grams

Explanation:

Molarity is calculated by using the equation:

Molarity of sucrose solution = 0.120 M

Volume of solution = 2.65 L

Rate law expression for first order kinetics is given by the equation:

where,

k = rate constant =

t = time taken for decay process = 200 min = (200 × 60) = 12000 seconds

= initial amount of the sample = 0.318 moles

[A] = amount left after decay process = ?

Putting values in above equation, we get:

To calculate the mass from given number of moles, we use the equation:

Moles of sucrose = 0.0367 moles

Molar mass of sucrose = 342.3 g/mol

Putting values in above equation, we get:

Hence, the mass of sucrose solution left is 12.56 grams

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