2 C2H6 + 7 O2 → 4 CO2 + 6 H2O
how many moles of ethane (C2H6) are required to produce 13.5 moles of water from the above reaction?

x = 4.5

4.5 moles of C2H6  is required to produce 13.5 moles of H2O

Explanation:

Given equation is :

2 C2H6 + 7 O2 → 4 CO2 + 6 H2O

if it requires 2 moles of C2H6 to produce 6 moles of H2O

then x moles of C2H6 is required to produce 13.5 moles of H2O

Using unitary method for solving, we get

x = 13.5 x 2 / 6

x = 13.5 / 3

x = 4.5

Therefore, 4.5 moles of C2H6  is required to produce 13.5 moles of H2O

Balanced Eqn

2

C

2

H

6

+

7

O

2

=

4

C

O

2

+

6

H

2

O

By the Balanced eqn

60g ethane requires 7x32= 224g oxygen

here ethane is in excess.oxygen will be fully consumed

hence

300g oxygen will consume  

60

⋅

300

224

=

80.36

g

ethane

leaving (270-80.36)= 189.64 g ethane.

By the Balanced eqn

60g ethane produces 4x44 g CO2

hence amount of CO2 produced =

4

⋅

44

⋅

80.36

60

=

235.72

g

and its no. of moles will be  

235.72

44

=5.36 where 44 is the molar mass of Carbon dioxideBalanced Eqn

2

C

2

H

6

+

7

O

2

=

4

C

O

2

+

6

H

2

O

By the Balanced eqn

60g ethane requires 7x32= 224g oxygen

here ethane is in excess.oxygen will be fully consumed

hence

300g oxygen will consume  

60

⋅

300

224

=

80.36

g

ethane

leaving (270-80.36)= 189.64 g ethane.

By the Balanced eqn

60g ethane produces 4x44 g CO2

hence amount of CO2 produced =

4

⋅

44

⋅

80.36

60

=

235.72

g

and its no. of moles will be  

235.72

44

=5.36 where 44 is the molar mass of Carbon dioxide

Explanation:

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates

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