A student made two solutions – solution A and solution B. Solution A contained 5 g of copper sulfate in 50 cm3 of water. Solution B contains 10 g of copper sulfate in 100 cm3 of water. The student added solution B to solution A. The student concluded that the new solution is more concentrated because it has more copper sulfate dissolved in it Is the student correct? Explain your answer

No. The student is wrong.

Explanation:

Concentration of solution = mole/volume

mole of 5 g of copper = 5/63.546 = 0.0787 mole

Concentration of A = 0.0787/0.05 = 1.57 M

mole of 10 g of copper = 10/63.546 = 0.1574 mole

Concentration of B = 0.1574/0.1 = 1.57 M

The two solution are added together:

Total concentration = total number of mole/total volume

                        = 0.0787 + 0.1574/0.05 + 0.1

                           = 0.2361/0.15

                             = 1.57 M

Hence, the new solution has the same concentration with solution A and solution B.

The student's conclusion was wrong.

i believe the answer is three water molecules