THIS IS FOR FIRE TECH

You are a fire captain and are called to look into a late-night overcrowding situation at a one-story department store during the holiday season. Based upon NFPA 5000, what would be the occupant load of the store if the floor area is 100,000 square feet (9,290 m^2)?

The answer to the question is;

The occupant load of the store having a floor area of 100,000 ft² is 3,317.86 persons.

Explanation:

Based on NFPA guidelines  we have for sales on street floor, the allowable occupant load factor per person is 30 ft²

That is where  the floor area is 100,000 square feet we have the number of allowable occupant given by

(100,000 ft²)/(30 ft²/Person) = or 3,333 persons

That is the  occupant load of the store if the floor area is 100,000 square feet = 3,333 persons

Based on m² we have  9,290 m² will require 2.8 m²/person

which gives;

(9,290 m²)/(2.8 m²/person) = = 23225/7 or 3,317.86 persons

Therefore applying safety, we go with the lesser number and we have

The occupant load of the store having a floor area of 9,290 m² = 3,317.86 persons.