A balloon has 0.3 moles of air inside and a volume of 7 liters after 0.2 more moles of air were blown into this balloon what is the volume

11.67L

Explanation:

From the ideal gas equation

PV = nRT

If all the variables ( i.e P and T) are kept constant, then the volume is directly proportional to n as shown below

V = nRT/P

RT/P ==> constant

V1/n1 = V2/n2

Data obtained from the question include:

n1 = 0.3mol

V1 = 7L

n2 = 0.3 + 0.2 = 0.5mol

V2=?

V1/n1 = V2/n2

7 /0.3 = V2 /0.5

Cross multiply to express in linear form

V2 x 0.3 = 7 x 0.5

Divide both side by 0.3

V2 = ( 7 x 0.5) /0.3

V2 = 11.67L

The new volume is 11.67L

just did the assignment and the answer was #1 +2 n

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml