Calculate the vapor pressure of spherical water droplets of radius (a) 17 nm and (b) 2.0 μm surrounded by water vapor at 298 K. The vapor pressure of water at this temperature is 25.2 Torr.

Explanation:

Relation between pressure of water and its droplet is as follows.

where,   p = pressure of droplet

          = water pressure in given temperature

          =

           M = Molecular Weight in Kg/Mol (0.018 for water)

            r = radius in meters

      = density of water in (1000 )

           R = ideal gas constant (8.31)

           T = temperature in Kelvin

(a)   We will calculate the value of p as follows.

           p =

              =

              = 26.8 torr

(b)  And, vapor pressure of spherical water droplets of radius 2.0 or

             p =

              =

              = 25.2 torr

thats a little if u want the answer just look it up on google thats what i do haha : )

the formula mass of a molecule or a compound is the sum of the atomic weights of the atoms in its empirical formula

(that's what i know about formula mass)