The concentration of copper(II) sulfate in one brand of soluble plant fertilizer is 0.070% by weight. If a 21.5 g sample of this fertilizer is dissolved in 2.0 L of solution, what is the molar concentration of Cu2

The molar concentration of ions in the given amount of sample is

Explanation:

Given that,

Mass of sample = 21.5 g

0.07 % (m/m) of copper (II) sulfate in plant fertilizer

This means that, in 100 g of plant fertilizer, 0.07 g of copper (II) sulfate is present

So, in 20 g of plant fertilizer

, of copper (II) sulfate is present.

To calculate the molarity of solution, we use the equation:

Mass of solute (copper (II) sulfate) = 0.0151 g

Molar mass of copper (II) sulfate = 159.6 g/mol

Volume of solution = 2.0 L

The chemical equation for the ionization of copper (II) sulfate follows:

1 mole of copper (II) sulfate produces 1 mole of copper (II) ions and sulfate ions

Molarity of copper (II) ions =

Hence, the molar concentration of ions in the given amount of sample is

i think   the answer is c hope i'm right