How many grams of lithium nitride needs to react with excess water at stp to produce 15.0 l of ammonia

Mass = 24.4 g

Explanation:

Given data:

Mass of lithium nitride needed = ?

Volume of ammonia = 15.0 L

Solution:

Chemical equation:

Li₃N + 3H₂O   → NH₃ + 3LiOH

One mole = 22.414 L

We will compare the volume of lithium  nitride and ammonia.

                                NH₃             :            Li₃N

                              22.414           :              22.414

                               15.0              :               15.0  

Number of moles of lithium nitride:

PV = nRT

n = 1 atm ×15 L / 0.0821 atm.L / mol.K × 273 K

n = 15 /22.41 /mol

n =0.7

Mass of Lithium nitride:

Mass = number of moles × molar mass

Mass = 0.7 mol × 34.83 g/mol

Mass = 24.4 g

b) mutualism

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explanation: