A gas currently has a pressure of 17 atm, a volume of 96 L, and a temperature of 284 K. If its initial
pressure was 16 atm and initial volume was 84 L, what was the initial temperature?

The initial temperature was 234K

Explanation:

We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T

(P1xV1)/T1=(P2xV2)/T2

(16atmx84L)/T1= (17atmx 96 L)/284K

1344atmx L/T1= 5,75 atm x L/K

T1= 1344atmx L/5,75 atm x L/K= 233,74K

the answer to your question is c.

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