What is the mass in grams of 15 L of nitrogen gas at STP

m = 18.76 g N2

Explanation: To solve for the mass of N2 we will use the formula of Ideal Gas Law and find first the number of moles of N2.

PV= nRT, derive for n.

n = PV /RT, at STP pressure is 1 atm and temperature is 273 K.

n= PV/RT

= 1 atm ( 15 L ) / 0.0821 L.atm/ mole K ( 273 K)

= 0.67 mole N2

Next convert moles of N2 to mass using the molar mass of Nitrogen gas.

0.67 mole N2 x 28 g N2 / 1 mole N2

= 18.76 g N2

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