Draw a hemiacetal, an acetal, and an imine that can be formed from propanal (C3H6O). Circle those that form in basic solution and place a star by those that form in acidic solution.

They are all formed in acidic solution.

Explanation:

The diagram for hemiacetal, acetal and imine is shown in the diagram below and a star is placed on the three of them since they are all form in acidic solution.

From the diagram; reaction of methanol with propanal leads to formation of hemiacetal. From CH₃OH(methanol), one hydrogen attaches itself to the Oxygen double bond on the propanal to form a new hydroxyl group, the other methoxyl (-O-CH₃) from methanol attaches itself to other part of the propanal.

The further addition of methanol to Hemiacetal yields to Acetal.

Imines are formed by Mannich Reaction  which is the  reaction of propanal with amine group and which is followed by the dehydration with a Schiff base.

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

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(jacemorris04)