How much mass of iodine would react with 48 grams of magnesium to make magnesium iodide?

Mg + I2 -> MgI2

Mass = 507.6 g

Explanation:

Given data:

Mass of Mg = 48 g

Mass of iodine react = ?

Solution:

Chemical equation:

Mg + I₂ → MgI₂

Now we will determine the number of moles of Mg.

Number of moles = mass/ molar mass

Number of moles = 48 g/ 24 g/mol

Number of moles = 2 mol

Now we will compare the moles of Mg with iodine.

                       Mg           :           I₂

                         1             :            1

                         2            :           2

Mass of iodine:

Mass = number of moles × molar mass

Mass = 2 mol × 253.8 g/mol

Mass = 507.6 g

nuclear fission produces elements that are heavier than helium.

the elements that are used in nuclear fission and their products are much heavier than helium.

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.