A galvanic cell is powered by the following redox reaction: 2Fe + 3(aq) + H2 (g) + 2OH−(aq) → 2Fe + 2(aq) + 2H2O(l)Answer the following questions about this cell. (a) Write a balanced equation for the half-reaction that takes place at the cathode. (b) Write a balanced equation for the half-reaction that takes place at the anode. (c) Calculate the cell voltage under standard conditions.

0.77V

Explanation:

The balanced anode and cathode half reaction equations are shown in the image attached. Reduction occurs at the cathode while oxidation occurs at the anode. Recall that hydrogen is a reference electrode hence its reduction potential is arbitrarily chosen as 0.00V under standard conditions. The hydroxide ion shows that the metal ion was maintained under alkaline conditions.

i believe the answer is a.