F 18.5 mL mL of 0.800 M HCl M HCl solution are needed to neutralize 5.00 mLmL of a household ammonia solution, what is the molar concentration of the ammonia

The molar concentration of the ammonia is 2.96 M.

Explanation:

In titration the known concentrated acid or base solution is added to unknown concentration solution until a neutral point is formed.

In titrations the formula used is

Macid x V acid = Mbase x V base

The volume must be in litre.

From the question it can be found that HCl is used to neutralize household ammonia.

Volume of HCl is 18.5 ml which is L

molarity of the HCl is given 0.8 M

Volume of the base NH3 is given 5ml which is L

Using the formula given above

Macid x V acid = Mbase x V base

Putting the values in the equation:

0.8 x 0.0185 = Mbase x 0.005

Mbase =  

  Mbase         = 2.96 M

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.