The gas left in a used aerosol can is at a pressure of 103 kPa at 25.0 °C. If the can heats up to 50.0 °C, what is the pressure of the gas inside the can, assuming the volume of the can is constant? A. 112 kPa B. 211 kPa C. 415 kPa D. 541 kPa

A.

112 kPa

Explanation:

We’ll use the combined gas law equation;

P₁V₁/T₁ = P₂V₂/T₂

Because the volume of the gas remains the same, then the V₁ and V₂ cancel out leaving us with;

P₁/T₁ = P₂/T₂

We can now replace the variables with the values given in the question. Remember to convert the temperatures to Kelvin;

25 degrees C = 298.15 K

50 degrees C = 323.15 K

103/298.15 = P₂/323.15

103/298.15 * 323.15 = P₂

111.63659 = P₂

= 112 kPa

do u have any choices to choose from ? ?

the potential energy of the reactants is 200j.

from the energy diagram, the energy of the product formed is 350j; this means that, this reaction is an endothermic reaction, because it absorbs energy from its environment.