A titration of vinegar with a solution of NaOH was performed. If 3.45 mL of vinegar needs 44.0 mL of 0.140 M NaOH to reach the equivalence point in a titration, Calculate the mass of acetic acid present in the vinegar sample: mastering chemistry answers

The mass of acetic acid present in the vinegar sample is 0.370 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

Molarity of NaOH solution = 0.140 M

Volume of solution = 44.0 mL

Putting values in above equation, we get:

The chemical equation for the reaction of acetic acid and NaOH follows:

By Stoichiometry of the reaction:

1 mole of NaOH reacts with 1 mole of acetic acid

So, 0.00616 moles of NaOH will react with = of acetic acid

To calculate the number of moles, we use the equation:

Molar mass of acetic acid = 60 g/mol

Moles of acetic acid = 0.00616 moles

Putting values in above equation, we get:

Hence, the mass of acetic acid present in the vinegar sample is 0.370 grams

answer

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just did the assignment and the answer was #1 +2 n