Chemistry, 10.03.2020 06:00 TrueKing184
The equilibrium constant, Kc , for the decomposition of COBr2 COBr2(g) ↔ CO(g) + Br2(g) is 0.190. What is Kc for the following reaction? 2CO(g) + 2Br2(g) ↔ 2COBr2(g)
Answers: 2
for the reaction.
![K_c=\frac{[CO][Br_2]}{[COBr_2]}](/tpl/images/0540/1501/c4707.png)
..[1]![K_c'=\frac{[COBr_2]^2}{[CO]^2[Br]^2}](/tpl/images/0540/1501/4595a.png)
( from [1])
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The equilibrium constant, Kc , for the decomposition of COBr2 COBr2(g) ↔ CO(g) + Br2(g) is 0.190. Wh...
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