Using the following equation how many grams of pure oxygen do you need to comsume 635.2g of glucose: C6H12O6 + 6O2 → 6CO2 + 6H2O + energy

The mass of grams of pure oxygen you need to consume 635.2g of glucose is 677.55 grams

Given the chemical reaction of glucose and oxygen represented as

Given the following

Mass of Glucose = 635.2g

Get the molar mass of glucose:

Molar mass of glucose = (6×12) + (1×12) + (6×16)

Molar mass of glucose= 72 + 12 + 96

Molar mass of glucose = 180g/mol

Number of moles of glucose =

Since Glucose reacted with 6 moles of oxygen:

Number of moles of reacted oxygen = 6 × 3.52 = 21.173moles

Find the grams of pure oxygen:

Hence the mass of grams of pure oxygen you need to consume 635.2g of glucose is 677.55 grams

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677.76 g of oxygen needed.

Explanation:

Given data:

Mass of glucose = 635.2 g

Mass of oxygen needed = ?

Solution:

Chemical equation:

C₆H₁₂O₆  + 6O₂  →  6CO₂ + 6H₂O + energy

Number of moles of glucose:

Number of moles = mass/ molar mass

Number of moles = 635.2 g / 180.156 g/mol

Number of moles = 3.53 mol

Now we will compare the moles of glucose with oxygen.

                         C₆H₁₂O₆           :              O₂

                               1                  :               6

                             3.53              :           6×3.53 = 21.18 mol

Mass of oxygen:

Mass = number of moles × molar mass

Mass =  21.18 g × 32 g/mol

Mass = 677.76 g

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