. In a separate experiment, the molar mass of nicotine is found to be somewhere between 150 and 180 g/mol. Calculate the molar mass of nicotine to the nearest gram

Explanation:

The question is incomplete. The complete question includes the information to find the empirical formula of nicotine:

Nicotine has the formula   . To determine its composition, a sample is burned in excess oxygen, producing the following results:

Assume that all the atoms in nicotine are present as products

To find the empirical formula you need to find the moles of C, H, and N in each of the compound.

Thus, the ratio of moles is:

Divide all by the smallest number: 0.20

Hence, the empirical formula is C₅H₇N

Find the mass of 1 mole of units of the empirical formula:

Total mass = 60g + 7g + 14g = 81g

Two moles of units of the empirical formula weighs 2 × 81g = 162g and three units weighs 3 × 81g = 243 g.

Thus, since the molar mass is between 150 and 180 g/mol, the correct molar mass is 162g/mol and the molecular formula is twice the empirical formula: C₁₀H₁₄N₂.

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