Doreen Schmidt is a chemist. She needs to prepare 28 ounces of a 12% hydrochloric acid solution. Find the amount of 14% solution and the amount of 7% solution she should mix to get this solution.

20 ounces of 14% solution and 8 ounces of 7% solution.

Explanation:

Let the amount of 14% solution required be A and the amount of 7% solution required be B.

Mixture of A and B must give 28 ounces:

A + B = 28 Eqn 1

Also, mixture of 14% A and 7% B must give 12%, 28 ounces solution:

0.14A + 0.07B = 0.12(28) = 3.36Eqn 2

From eqn 1, B = 28 - A, eqn 2 becomes:

0.14A + 0.07(28 - A) = 3.36

0.07A = 3.36 - 1.96

A = 20 ounces

Substitute the value of A into eqn 1 to get B:

20 + B = 28

B = 8 ounces.

Hence, 20 ounces of 14% hydrochloric acid and 8 ounces of 7% hydrochoric acid should be mixed together in order to get 28 ounces of 12% solution.

the correct answer is answer a. a mixture

no other options make sense

hope this

have a great day : )

  - sprinkles

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm