What is the concentration of iron(iii) chloride in a solution prepared by dissolving 15.0 g of iron(iii) chloride in enough water to make 575 ml of solution

[FeCl₃] = 0.16M

Explanation:

The components of our solution is:

Solute: FeCl₃ (15 g)

Solvent: Water

Solution: Volume of 575 mL

In order to determine the concentration (M) we have to find out the moles of our solute and think, that they occupy 1L of solution's volume

Molarity (mol/L) = M

We convert the mass of solute in moles → 15 g / 162.2 g/mol = 0.092 moles

We convert the solution's volume from mL to L → 575 mL .1L /1000mL = 0.575L

Molarity → 0.092 mol/0.575L = 0.16 M

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