Aqueous hydrochloric acid reacts with aqueous sodium sulfite to produce aqueous sodium chloride and aqueous sulfurous acid. Write a balanced chemical equation for this reaction.

2HCl(aq) + Na2SO3(aq) —> 2NaCl(aq) + H2SO3(aq)

Explanation:

HCl(aq) + Na2SO3(aq) —> NaCl(aq) + H2SO3(aq)

Let us balance the equation. This is illustrated below:

There are 2 atoms of Na on the left side of the equation and 1atom on the right side. It can be balance by putting 2 in front of NaCl as shown below:

HCl(aq) + Na2SO3(aq) —> 2NaCl(aq) + H2SO3(aq)

Now, we have 2 atoms of Cl on the right side and 1 atom on the left side. Thus, it can be balance by putting 2 in front of HCl as shown below:

2HCl(aq) + Na2SO3(aq) —> 2NaCl(aq) + H2SO3(aq)

A careful look at the equation proved that the equation is balanced as the numbers of the different atoms of the element on both side of the equation are the same.

2HCl (aq) + Na₂SO₃ (aq) → 2NaCl (aq) + H₂SO₃(aq)

Explanation:

We identify the reactants with its phases:

HCl (aq)

Na₂SO₃ (aq)

We identify the products:

NaCl(aq)

H₂SO₃ (aq)

We dissociates the reactants:

HCl (aq) + Na₂SO₃ (aq) → H⁺ + Cl⁻ + 2Na⁺ + SO₃⁻²

2H⁺ will bond the SO₃⁻² to make the acid

and the Cl⁻ will bond the Na⁺ to make the salt

The balanced equation is:

2HCl (aq) + Na₂SO₃ (aq) → 2NaCl + H₂SO₃

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