An equilibrium mixture of CO, O2 and CO2 at a certain temperature contains 0.0010 M CO2 and 0.0025 M O2. At this temperature, Kc equals 1.4 × 102 for the reaction: 2 CO(g) + O2(g) ⇌ 2 CO2(g). What is the equilibrium concentration of CO?

M

Explanation:

Equation for the reaction is as follows:

     +              ⇄      

By Applying the ICE Table; we have

                                   +              ⇄      

Initial                      x                  0.0025 M              0.0010 M

Change                  0                       0                            0

Equilibrium             x                  0.0025 M              0.0010 M

Given that ; Then:

M

∴ The equilibrium concentration of CO = M

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong

you gotta add the following molecules so we can give u an answer

explanation: