How many atoms of oxygen in 89.2 g of aspartame

Answer and Explanation:

Molecular formula if aspartame is C14H18N2O5. Its molar mass is ~294 g/mol.

Firstly we need to calculate moles of aspartame. This can be done by converting 89.2 grams into moles,

89.2 g / 294 g/mol = 0.303 moles of aspartame

Each mole of aspartame has 5 moles of oxygen. So, we will have 1.517 moles of O in 89.2 grams of aspartame (5 x 0.303).

Finally, we can calculate the number of O atoms by multiplying with avogadro's number

= 1.517 mol X 6.02 X 10^23

= 9.13 X 10^23 oxygen atoms.

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm