A 2.0 mol sample of ammonia is introduced into a 1.00 L container. At a certain temperature, the ammonia partially dissociates according to the equation: NH_3(g) N_2(g) + H_2(g) At equilibrium 1.00 mol of ammonia remains. Calculate the value for K.

K = 1.69M

Explanation:

For the reaction:

2NH₃(g) ⇄ N₂(g) + 3H₂(g)

K is defined as:

k = [N₂] [H₂]³ / [NH₃]² (1)

Molarity in equilibrium for each specie is:

NH₃(g): 2.0mol - 2x = 1.0mol/1L = 1M → X = 0.5mol

N₂(g): X = 0.5mol/1L = 0.5M

H₂(g): 3X = 1.5mol/1L = 1.5M

Replacing:

k = [0.5] [1.5]³ / [1]²

k = 1.69M

I hope it helps!

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explanation:

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.