Calculate the volume of a 0.5M solution containing 20g of NaOH

1L

Explanation:

First, let us calculate the number of mole present in 20g of NaOH. This is illustrated below:

Mass = 20g

Molar Mass of NaOH = 23 + 16 + 1 = 40g/mol

Number of mole =?

Number of mole = Mass /Molar Mass

Number of mole of NaOH = 20/40 = 0.5mol

From the question given, we obtained the following data:

Molarity = 0.5M

Mole = 0.5mole

Volume =?

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 0.5/0.5

Volume = 1L

1L

Explanation:

Molar mass of NaOH is 40g/mol

Mass given is 20g

Number of moles=mass given/molar mass

Number of moles=20/40

Number of moles=0.5 moles

Volume=molarity/number of moles

Molarity=0.5M

Volume=0.5/0.5

Volume= 1

Therefore the volume is 1L

the dissociation of nickel hydroxide is follows:

the concentration of hydroxide ion is

the equilibrium constant value of nickel hydroxide is = 6.1 * 10^-^1^6 and thus equilibrium equation can be written as:

thus, concentration of ni is 0.23 * 10^-^4 mol /l